BRIX · NSR-10

C-F — Equivalencia entre el sistema SI, el sistema mks, y el sistema inglés de las ecuaciones no homogéneas del Título C del Reglamento

Tabla de equivalencias de las ecuaciones no homogéneas del Título C en los tres sistemas de unidades: resistencias, desarrollo del refuerzo, cortante, torsión, preesforzado, muros, concreto simple y anclajes.

Equivalencia entre el sistema SI, el sistema mks, y el sistema inglés de las ecuaciones no homogéneas del Título C del Reglamento
ReferenciaSistema SI — esfuerzos en MPaSistema mks — esfuerzos en kgf/cm²Sistema inglés — esfuerzos en libras por pulgada cuadrada (psi)
1 MPa10 kgf/cm²142.2 psi
f′c = 21 MPaf′c = 210 kgf/cm²f′c = 3,000 psi
f′c = 28 MPaf′c = 280 kgf/cm²f′c = 4,000 psi
f′c = 35 MPaf′c = 350 kgf/cm²f′c = 5,000 psi
f′c = 40 MPaf′c = 420 kgf/cm²f′c = 6,000 psi
fy = 280 MPafy = 2 800 kgf/cm²fy = 40,000 psi
fy = 420 MPafy = 4 200 kgf/cm²fy = 60,000 psi
fpu = 1 725 MPafpu = 17 600 kgf/cm²fpu = 250,000 psi
fpu = 1 860 MPafpu = 19 000 kgf/cm²fpu = 270,000 psi
√f′c en MPa3.18√f′c en kgf/cm²12√f′c en psi
0.313√f′c en MPa√f′c en kgf/cm²3.77√f′c en psi
0.083√f′c en MPa0.27√f′c en kgf/cm²√f′c en psi
0.17√f′c en MPa0.53√f′c en kgf/cm²2√f′c en psi
(C.5-2)f′cr = f′c + 2.33 ss − 3.5f′cr = f′c + 2.33 ss − 35f′cr = f′c + 2.33 ss − 500
Tabla C.5.3.2.2f′cr = f′c + 7.0f′cr = f′c + 70f′cr = f′c + 1000
Tabla C.5.3.2.2f′cr = f′c + 8.3f′cr = f′c + 84f′cr = f′c + 1200
Tabla C.5.3.2.2f′cr = 1.10 f′c + 5.0f′cr = 1.10 f′c + 50f′cr = 1.10 f′c + 700
Sección C.7.12.2.1(c)0.0018 × 420 / fy0.0018 × 4 200 / fy0.0018 × 60,000 / fy
Sección C.8.5.1Ec = wc^1.5 0.043√f′cEc = wc^1.5 0.14√f′cEc = wc^1.5 33√f′c
Sección C.8.5.1Ec = 4 700√f′cEc = 15100√f′cEc = 57,000√f′c
Sección C.8.6.1λ = fct / (0.56√f′c) ≤ 1.0λ = fct / (1.78√f′c) ≤ 1.0λ = fct / (6.7√f′c) ≤ 1.0
Tabla C.9.5(a)(1.65 − 0.0003wc) ≥ 1.09 ; (0.4 + fy / 700)(1.65 − 0.0003wc) ≥ 1.09 ; (0.4 + fy / 7000)(1.65 − 0.005wc) ≥ 1.09 ; (0.4 + fy / 100,000)
(C.9-10)fr = 0.62λ√f′cfr = 2λ√f′cfr = 7.5λ√f′c
(C.9-12)h = ℓn (0.8 + fy / 1400) / (36 + 5β(αfm − 0.2)) ≥ 125 mmh = ℓn (0.8 + fy / 14000) / (36 + 5β(αfm − 0.2)) ≥ 12.5 cmh = ℓn (0.8 + fy / 200,000) / (36 + 5β(αfm − 0.2)) ≥ 5 in.
(C.9-13)h = ℓn (0.8 + fy / 1400) / (36 + 9β) ≥ 90 mmh = ℓn (0.8 + fy / 14000) / (36 + 9β) ≥ 9 cmh = ℓn (0.8 + fy / 200,000) / (36 + 9β) ≥ 3.5 in.
(C.10-3)As,min = (0.25√f′c / fy) bw d ≥ (1.4 / fy) bw dAs,min = (0.8√f′c / fy) bw d ≥ (14 / fy) bw dAs,min = (3√f′c / fy) bw d ≥ (200 / fy) bw d
(C.10-4)s = 380 (280 / fs) − 2.5cc ≤ 300 (280 / fs)s = 38 (2800 / fs) − 2.5cc ≤ 30 (2800 / fs)s = 15 (40,000 / fs) − 2.5cc ≤ 12 (40,000 …
(C.10-17)M2,min = Pu (15 + 0.03h)M2,min = Pu (1.5 + 0.03h)M2,min = Pu (0.6 + 0.03h)
Sección C.11.1.2√f′c ≤ 8.3 MPa√f′c ≤ 27 kgf / cm²√f′c ≤ 100 psi
(C.11-3)Vc = 0.17λ√f′c bw dVc = 0.53λ√f′c bw dVc = 2λ√f′c bw d
(C.11-4)Vc = 0.17 (1 + Nu / (14Ag)) λ√f′c bw dVc = 0.53 (1 + Nu / (140Ag)) λ√f′c bw dVc = 2 (1 + Nu / (2000Ag)) λ√f′c bw d
(C.11-5)Vc = (0.16λ√f′c + 17ρw Vu d / Mu) bw d ≤ 0.29λ√f′c bw dVc = (0.5λ√f′c + 176ρw Vu d / Mu) bw d ≤ 0.93λ√f′c bw dVc = (1.9λ√f′c + 2500ρw Vu d / Mu) bw d ≤ 3.5λ√f′c bw d
(C.11-7)Vc = 0.29λ√f′c bw d √(1 + 0.29Nu / Ag)Vc = 0.93λ√f′c bw d √(1 + Nu / (35Ag))Vc = 3.5λ√f′c bw d √(1 + Nu / (500Ag))
(C.11-8)Vc = 0.17 (1 + 0.29Nu / Ag) λ√f′c bw d ≥ 0Vc = 0.53 (1 + Nu / (35Ag)) λ√f′c bw d ≥ 0Vc = 2 (1 + Nu / (500Ag)) λ√f′c bw d ≥ 0
(C.11-9)Vc = (0.05λ√f′c + 4.8 Vu dp / Mu) bw d ; 0.17λ√f′c bw d ≤ Vc ≤ 0.42λ√f′c bw dVc = (0.16λ√f′c + 49 Vu dp / Mu) bw d ; 0.53λ√f′c bw d ≤ Vc ≤ 1.33λ√f′c bw dVc = (0.6λ√f′c + 700 Vu dp / Mu) bw d ; 2λ√f′c bw d ≤ Vc ≤ 5λ√f′c bw d
(C.11-10)Vci = 0.05λ√f′c bw dp + Vd + Vi Mcre / Mmax ≥ 0.14λ√f′c bw dVci = 0.16λ√f′c bw dp + Vd + Vi Mcre / Mmax ≥ 0.45λ√f′c bw dVci = 0.6λ√f′c bw dp + Vd + Vi Mcre / Mmax ≥ 1.7λ√f′c bw d
(C.11-11)Mcre = (I / yt) (0.5λ√f′c + fpe − fd)Mcre = (I / yt) (1.6λ√f′c + fpe − fd)Mcre = (I / yt) (6λ√f′c + fpe − fd)
(C.11-12)Vcw = (0.29λ√f′c + 0.3fpc) bw dp + Vp ; 0.33λ√f′cVcw = (0.93λ√f′c + 0.3fpc) bw dp + Vp ; 1.1λ√f′cVcw = (3.5λ√f′c + 0.3fpc) bw dp + Vp ; 4λ√f′c
Sección C.11.4.5.30.33√f′c bw d1.1√f′c bw d4√f′c bw d
Sección C.11.4.6.1(f)φ0.17√f′c bw dφ0.53√f′c bw dφ2√f′c bw d
(C.11-13)Av,min = 0.062√f′c bw s / fyt ≥ 0.35 bw s / fytAv,min = 0.2√f′c bw s / fyt ≥ 3.5 bw s / fytAv,min = 0.75√f′c bw s / fyt ≥ 50 bw s / fyt
(C.11-17)Vs = Av fy senα ≤ 0.25√f′c bw dVs = Av fy senα ≤ 0.8√f′c bw dVs = Av fy sinα ≤ 3√f′c bw d
Sección C.11.4.7.90.66√f′c bw d2.2√f′c bw d8√f′c bw d
Sección C.11.5.1 (a)Tu < φ0.083λ√f′c (Acp² / pcp)Tu < φ0.27λ√f′c (Acp² / pcp)Tu < φλ√f′c (Acp² / pcp)
Sección C.11.5.1 (b)Tu < φ0.083λ√f′c (Acp² / pcp) √(1 + fpc / (0.33λ√ …Tu < φλ0.27√f′c (Acp² / pcp) √(1 + fpc / (λ√f′c))Tu < φλ√f′c (Acp² / pcp) √(1 + fpc / (4λ√f′c))
Sección C.11.5.1 (c)Tu < φ0.083λ√f′c (Acp² / pcp) √(1 + Nu / (0.33Ag …Tu < φ0.27λ√f′c (Acp² / pcp) √(1 + Nu / (Ag λ√ …Tu < φλ√f′c (Acp² / pcp) √(1 + Nu / (4Ag λ√f′c))
Sección C.11.5.2.2(a)Tu = φ0.33λ√f′c (Acp² / pcp)Tu = φλ√f′c (Acp² / pcp)Tu = φ4λ√f′c (Acp² / pcp)
Sección C.11.5.2.2(b)Tu = φ0.33λ√f′c (Acp² / pcp) √(1 + fpc / (0.33λ√f …Tu = φλ√f′c (Acp² / pcp) √(1 + fpc / (λ√f′c))Tu = φ4λ√f′c (Acp² / pcp) √(1 + fpc / (4λ√f′c))
Sección C.11.5.2.2(c)Tu = φ0.33λ√f′c (Acp² / pcp) √(1 + Nu / (0.33Ag λ …Tu = φλ√f′c (Acp² / pcp) √(1 + Nu / (Ag λ√f′c))Tu = φ4λ√f′c (Acp² / pcp) √(1 + Nu / (4Ag λ√f′c))
(C.11-18)√[(Vu / (bw d))² + (Tu ph / (1.7A0h²))²] ≤ φ (Vc / (bw d) + 0.66√f′c)√[(Vu / (bw d))² + (Tu ph / (1.7A0h²))²] ≤ φ (Vc / (bw d) + 2√f′c)√[(Vu / (bw d))² + (Tu ph / (1.7A0h²))²] ≤ φ (Vc / (bw d) + 8√f′c)
(C.11-19)(Vu / (bw d)) + (Tu ph / (1.7A0h²)) ≤ φ (Vc / (bw d) + 0.66√f′c)(Vu / (bw d)) + (Tu ph / (1.7A0h²)) ≤ φ (Vc / (bw d) + 2√f′c)(Vu / (bw d)) + (Tu ph / (1.7A0h²)) ≤ φ (Vc / (bw d) + 8√f′c)
(C.11-23)(Av + 2At) = 0.062√f′c bw s / fyt ≥ 0.35 bw s / fyt(Av + 2At) = 0.2√f′c bw s / fyt ≥ 3.5 bw s / fyt(Av + 2At) = 0.75√f′c bw s / fyt ≥ 50 bw s / fyt
(C.11-24)Aℓ,min = 0.42√f′c Acp / fy − (At / s) ph fyt / fy ; At / s ≥ 0.175 bw / fytAℓ,min = 1.33√f′c Acp / fy − (At / s) ph fyt / fy ; At / s ≥ 1.75 bw / fytAℓ,min = 5√f′c Acp / fy − (At / s) ph fyt / fy ; At / s ≥ 25 bw / fyt
Sección C.11.6.5(3.3 + 0.08f′c) Ac ; 11Ac ; 5.5Ac(34 + 0.08f′c) Ac ; 110Ac ; 55Ac(480 + 0.08f′c) Ac ; 1600Ac ; 800Ac
Sección C.11.7.30.83√f′c bw d2.65√f′c bw d10√f′c bw d
Sección C.11.8.3.2.1(3.3 + 0.08f′c) bw d ; 11bw d(34 + 0.08f′c) bw d ; 110bw d(480 + 0.08f′c) bw d ; 1600bw d
Sección C.11.8.3.2.2(5.5 − 1.9 av / d) bw d(55 − 20 av / d) bw d(800 − 280 av / d) bw d
Sección C.11.9.30.83√f′c h d2.65√f′c h d10√f′c h d
Sección C.11.9.50.17λ√f′c h d0.53λ√f′c h d2λ√f′c h d
(C.11-27)Vc = 0.27λ√f′c h d + Nu d / (4ℓw)Vc = 0.88λ√f′c h d + Nu d / (4ℓw)Vc = 3.3λ√f′c h d + Nu d / (4ℓw)
(C.11-28)Vc = [0.05λ√f′c + ℓw (0.1λ√f′c + 0.2 …) / (Mu / Vu − ℓw / 2) …Vc = [0.16λ√f′c + ℓw (0.33λ√f′c + 0.2 …) / (Mu / Vu − ℓw / 2) …Vc = [0.6λ√f′c + ℓw (1.25λ√f′c + 0.2 …) / (Mu / Vu − ℓw / 2) …
(C.11-31)Vc = 0.17 (1 + 2 / β) λ√f′c bo dVc = 0.53 (1 + 2 / β) λ√f′c bo dVc = (2 + 4 / β) λ√f′c bo d
(C.11-32)Vc = 0.083 (αs d / bo + 2) λ√f′c bo dVc = 0.27 (αs d / bo + 2) λ√f′c bo dVc = (αs d / bo + 2) λ√f′c bo d
(C.11-33)Vc = 0.33λ√f′c bo dVc = λ√f′c bo dVc = 4λ√f′c bo d
(C.11-34)Vc = (βp λ√f′c + 0.3fpc) bo d + Vp ; Nota: βp tiene unidadesVc = (3.16βp λ√f′c + 0.3fpc) bo d + Vp ; Nota: βp tiene las mismas unidades que la versión SIVc = (βp λ√f′c + 0.3fpc) bo d + Vp ; Nota: βp tiene unidades
Sección C.11.11.2.2√f′c ≤ 0.5 MPa√f′c ≤ 5 kgf / cm²√f′c ≤ 70 psi
Sección C.11.11.3.10.17λ√f′c bo d0.53λ√f′c bo d2λ√f′c bo d
Sección C.11.11.3.20.5√f′c bo d1.6√f′c bo d6√f′c bo d
Sección C.11.11.4.80.33√f′c bo d ; 0.58√f′c bo d1.1√f′c bo d ; 1.9√f′c bo d4√f′c bo d ; 7√f′c bo d
Sección C.11.11.5.10.25λ√f′c bo d ; 0.66√f′c bo d ; 0.17√f′c0.8λ√f′c bo d ; 2.1√f′c bo d ; 0.53√f′c3λ√f′c bo d ; 8√f′c bo d ; 2√f′c
Sección C.11.11.5.20.5φ√f′c1.6φ√f′c6φ√f′c
Sección C.11.11.5.40.17φλ√f′c0.53φλ√f′c2φλ√f′c
Sección C.11.11.7.20.17φλ√f′c0.53φλ√f′c2φλ√f′c
Sección C.11.11.7.30.33φλ√f′c1.1φλ√f′c4φλ√f′c
Sección C.12.1.2√f′c ≤ 8.3 MPa√f′c ≤ 26.5 kgf / cm²√f′c ≤ 100 psi
Sección C.12.2.2ℓd = (fy ψt ψe / (2.1λ√f′c)) dbℓd = (fy ψt ψe / (6.6λ√f′c)) dbℓd = (fy ψt ψe / (25λ√f′c)) db
Sección C.12.2.2ℓd = (fy ψt ψe / (1.7λ√f′c)) dbℓd = (fy ψt ψe / (5.3λ√f′c)) dbℓd = (fy ψt ψe / (20λ√f′c)) db
Sección C.12.2.2ℓd = (fy ψt ψe / (1.4λ√f′c)) dbℓd = (fy ψt ψe / (4.4λ√f′c)) dbℓd = (3fy ψt ψe / (50λ√f′c)) db
Sección C.12.2.2ℓd = (fy ψt ψe / (1.1λ√f′c)) dbℓd = (fy ψt ψe / (3.5λ√f′c)) dbℓd = (3fy ψt ψe / (40λ√f′c)) db
(C.12-1)ℓd = (fy / (1.1λ√f′c)) (ψt ψe ψs / ((cb + Ktr) / db)) dbℓd = (fy / (3.5λ√f′c)) (ψt ψe ψs / ((cb + Ktr) / db)) dbℓd = (3fy / (40λ√f′c)) (ψt ψe ψs / ((cb + Ktr) / db)) db
Sección C.12.3.2(0.24fy / (λ√f′c)) db ≥ (0.043fy) db(0.075fy / (λ√f′c)) db ≥ (0.0044fy) db(0.02fy / (λ√f′c)) db ≥ (0.0003fy) db
Sección C.12.5.2ℓdh = (0.24ψe fy / (λ√f′c)) dbℓdh = (0.075ψe fy / (λ√f′c)) dbℓdh = (0.02ψe fy / (λ√f′c)) db
Sección C.12.6.2ℓdh = (0.19ψe fy / √f′c) dbℓdh = (0.06ψe fy / √f′c) dbℓdh = (0.016ψe fy / √f′c) db
Sección C.12.7.2(fy − 240) / fy(fy − 2 460) / fy(fy − 35,000) / fy
(C-12-3)ℓd = 3.3 (Ab / s) (fy / (λ√f′c))ℓd = (Ab / s) (fy / (λ√f′c))ℓd = 0.27 (Ab / s) (fy / (λ√f′c))
(C-12-4)ℓd = (fse / 21) db + ((fps − fse) / 7) dbℓd = (fse / 210) db + ((fps − fse) / 70) dbℓd = (fse / 3000) db + ((fps − fse) / 1000) db
Sección C.12.10.5.20.41 bw s / fyt4.2 bw s / fyt60 bw s / fyt
Sección C.12.13.2.20.17 db fyt / (λ√f′c)0.053 db fyt / (λ√f′c)0.014 db fyt / (λ√f′c)
Sección C.12.16.10.071fy db ; (0.13fy − 24) db0.0073fy db ; (0.013fy − 24) db0.0005fy db ; (0.0009fy − 24) db
Sección C.17.5.3.1 y C.17.5.3.20.55 bv d5.6 bv d80 bv d
Sección C.17.5.3.3(1.8 + 0.6ρv fy) λ bv d ≤ 3.5 bv d(18 + 0.6ρv fy) λ bv d ≤ 35 bv d(260 + 0.6ρv fy) λ bv d ≤ 500 bv d
Sección C.18.3.3(a) Clase U: ft ≤ 0.62√f′c ; (b) Clase T: 0.62√f′c < ft ≤ 1.0√f′c ; (c) Clase C: ft > 1.0√f′c ; ft ≤ 0.50√f′ci(a) Clase U: ft ≤ 2√f′c ; (b) Clase T: 2√f′c < ft ≤ 3.2√f′c ; (c) Clase C: ft > 3.2√f′c ; ft ≤ 1.6√f′ci(a) Clase U: ft ≤ 7.5√f′c ; (b) Clase T: 7.5√f′c < ft ≤ 12√f′c ; (c) Clase C: ft > 12√f′c ; ft ≤ 6√f′ci
Sección C.18.4.1(c)0.50√f′ci ; 0.25√f′ci1.6√f′ci ; 0.8√f′ci6√f′ci ; 3√f′ci
(C.18-4)fps = fse + 70 + f′c / (100ρp)fps = fse + 700 + f′c / (100ρp)fps = fse + 10,000 + f′c / (100ρp)
(C.18-5)fps = fse + 70 + f′c / (300ρp)fps = fse + 700 + f′c / (300ρp)fps = fse + 10,000 + f′c / (300ρp)
Secciones C.18.9.3.1 y C.18.9.3.20.17√f′c0.53√f′c2√f′c
Sección C.18.12.72.1 bw d / fy21 bw d / fy300 bw d / fy
Sección C.18.13.4.1fps = fse + 70fps = fse + 700fps = fse + 10,000
Sección C.19.4.100.33φλ√f′c1.1φλ√f′c4φλ√f′c
Sección C.21.5.2.11.4 bw d / fy14 bw d / fy200 bw d / fy
(C.21-2)so = 100 ((350 − hx) / 3) ; 100 mm ≤ so ≤ 150 mmso = 10 ((35 − hx) / 3) ; 10 cm ≤ so ≤ 15 cmso = 4 ((14 − hx) / 3) ; 4 in. ≤ so ≤ 6 in.
Sección C.21.7.4.11.7√f′c Aj ; 1.2√f′c Aj ; 1.0√f′c Aj5.3√f′c Aj ; 4√f′c Aj ; 3.2√f′c Aj20√f′c Aj ; 15√f′c Aj ; 12√f′c Aj
(C.21-6)ℓdh = fy db / (5.4√f′c)ℓdh = fy db / (17.2√f′c)ℓdh = fy db / (65√f′c)
Sección C.21.9.2.10.083Acv λ√f′c0.27Acv λ√f′cAcv λ√f′c
Sección C.21.9.2.20.17Acv λ√f′c0.53Acv λ√f′c2Acv λ√f′c
(C.21-7)Vn = Acv (αc λ√f′c + ρt fy) ; αc = 0.25 para hw / ℓw ≤ 1.5 ; αc = 0.17 para hw / ℓw ≥ 2.0Vn = Acv (αc λ√f′c + ρt fy) ; αc = 0.80 para hw / ℓw ≤ 1.5 ; αc = 0.53 para hw / ℓw ≥ 2.0Vn = Acv (αc λ√f′c + ρt fy) ; αc = 3.0 para hw / ℓw ≤ 1.5 ; αc = 2.0 para hw / ℓw ≥ 2.0
Sección C.21.9.4.40.66Acv√f′c ; 0.83Acw√f′c2.12 Acv√f′c ; 2.65Acw√f′c8 Acv√f′c ; 10Acw√f′c
Sección C.21.9.4.50.83Acw√f′c2.65Acw√f′c10Acw√f′c
Sección C.21.9.6.5(a)2.8 / fy28 / fy400 / fy
Sección C.21.9.6.5(b)0.083Acv λ√f′c0.27Acv λ√f′cAcv λ√f′c
Sección C.21.9.7.20.33λ√f′c Acwλ√f′c Acw4λ√f′c Acw
(C.21-9)Vn = 2Avd fy senα ≤ 0.83√f′c AcwVn = 2Avd fy senα ≤ 2.65√f′c AcwVn = 2Avd fy sinα ≤ 10√f′c Acw
(C.21-10)Vn = Acv (0.17λ√f′c + ρt fy)Vn = Acv (0.53λ√f′c + ρt fy)Vn = Acv (2λ√f′c + ρt fy)
Sección C.21.11.9.20.66Acv√f′c2.12 Acv√f′c8 Acv√f′c
Sección C.21.13.60.29√f′c bo d0.93√f′c bo d3.5√f′c bo d
(C.22-2)Mn = 0.42λ√f′c SmMn = 1.33λ√f′c SmMn = 5λ√f′c Sm
(C.22-7)Mu / Sm − Pu / Ag ≤ φ0.42λ√f′cMu / Sm − Pu / Ag ≤ φ1.33λ√f′cMu / Sm − Pu / Ag ≤ φ5λ√f′c
(C.22-9)Vn = 0.11λ√f′c bw hVn = 0.35λ√f′c bw hVn = (4λ√f′c / 3) bw h
(C.22-10)Vn = 0.11 [1 + 2 / β] λ√f′c bo h ≤ 0.22λ√f …Vn = 0.35 [1 + 2 / β] λ√f′c bo h ≤ 0.71λ√f …Vn = [4 / 3 + 8 / (3β)] λ√f′c bo h ≤ 2.66λ√f′c b …
(C-B-1)ρb = (0.85β1 f′c / fy) (600 / (600 + fy))ρb = (0.85β1 f′c / fy) (6120 / (6120 + fy))ρb = (0.85β1 f′c / fy) (87,000 / (87,000 + fy))
(C-D-7)Nb = kc λ√f′c hef^1.5 ; kc = 10 ó 7Nb = kc λ√f′c hef^1.5 ; kc = 10 ó 7Nb = kc λ√f′c hef^1.5 ; kc = 24 ó 17
(C-D-8)Nb = 3.9λ√f′c hef^(5/3)Nb = 5.8λ√f′c hef^(5/3)Nb = 16λ√f′c hef^(5/3)
(C-D-17)Nsb = 13ca1 √Abrg λ√f′cNsb = 42.5ca1 √Abrg λ√f′cNsb = 160ca1 √Abrg λ√f′c
(C-D-24)Vb = 0.6(ℓe / da)^0.2 √da λ√f′c (ca1)^1.5Vb = 1.9(ℓe / da)^0.2 √da λ√f′c (ca1)^1.5Vb = 7(ℓe / da)^0.2 √da λ√f′c (ca1)^1.5
(C-D-25)Vb = 0.66(ℓe / da)^0.2 √da λ√f′c (ca1)^1.5Vb = 2.1(ℓe / da)^0.2 √da λ√f′c (ca1)^1.5Vb = 8(ℓe / da)^0.2 √da λ√f′c (ca1)^1.5